PAT Advanced 1036 Boys vs Girls (25 分)

PAT Advanced 1036 Boys vs Girls (25 分)
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大家好,我是架构君,一个会写代码吟诗的架构师。今天说一说PAT Advanced 1036 Boys vs Girls (25 分),希望能够帮助大家进步!!!

This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's namegenderID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF​​gradeM​​. If one such kind of student is missing, output Absent in the corresponding line, and output NA in the third line instead.

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

Sample Output 1:

Mary EE990830
Joe Math990112
6

Sample Input 2:

1
Jean M AA980920 60

Sample Output 2:

Absent
Jean AA980920
NA



#include <iostream>
using namespace std;
struct stu{
    string name;
    char gender;
    string id;
    int grade;
};
int main()
{
    int N;cin>>N;
    bool male=false,female=false;
    stu tmp,maleLowest,femaleHighest;
    while(N--){
        cin>>tmp.name>>tmp.gender>>tmp.id>>tmp.grade;
        if(tmp.gender=='M'){
            /**性别为M*/
            if(male==false){
                male=!male;
                maleLowest=tmp;
            }else{
                if(maleLowest.grade>tmp.grade){
                    maleLowest=tmp;
                }
            }
        }else{
            /**性别为F*/
            if(female==false){
                female=!female;
                femaleHighest=tmp;
            }else{
                if(femaleHighest.grade<tmp.grade){
                    femaleHighest=tmp;
                }
            }
        }
    }
    /**output*/
    if(female==false) cout<<"Absent"<<endl;
    else cout<<femaleHighest.name<<" "<<femaleHighest.id<<endl;
    if(male==false) cout<<"Absent"<<endl;
    else cout<<maleLowest.name<<" "<<maleLowest.id<<endl;
    if(male==false||female==false) cout<<"NA"<<endl;
    else cout<<(femaleHighest.grade-maleLowest.grade)<<endl;
    system("pause");
    return 0;
}

 



转载于:https://www.cnblogs.com/littlepage/p/11292215.html

本文来源weixin_30595035,由架构君转载发布,观点不代表Java架构师必看的立场,转载请标明来源出处:https://javajgs.com/archives/29547

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